Question

(х+у=7) (3х+2у=16) ​

Answer 1

$(x + y = 7 \div 2 \\ 3x + 2y = 16) \\ \\ \\ - (2x + 2y = 14 \\ 3x + 2y = 16) \\ \\ \\ - x = - 2 \\ x = 2 \\ \\ \\ \\ 2 + y = 7 \\ y = 5$

ответ х =2 ;у =5