Question

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Answer 1

$\frac{26}{4- \sqrt{3} } - \frac{5}{3+2 \sqrt{2} } - \sqrt{2} (10+ \sqrt{6} )= \\ \\ \frac{26}{4- \sqrt{3} }* \frac{4+ \sqrt{3}}{4+ \sqrt{3}} - \frac{5}{3+2 \sqrt{2} } * \frac{3-2 \sqrt{2}}{3-2 \sqrt{2}} - \sqrt{2} (10+ \sqrt{6} )= \\ \\ \frac{104+26 \sqrt{3} }{16-3} - \frac{15-10 \sqrt{2} }{9-8} -\sqrt{2} (10+ \sqrt{6} )= \\ \\ 8+2 \sqrt{3} -15+10 \sqrt{2} -10 \sqrt{2} - \sqrt{12} = \\ \\ -7+\sqrt{12}-\sqrt{12}=-7$