Находим массу чисього алюминия:, его 90%-598,5*90%/100%=538,65
538.65 x
составляем уравнение:2Al+3Cl2=2AlCl3
2*27 2*(27+35.5*3)
54 267
538.65-----------------x
54--------------------267
x=538.65*267/54=2663.325гр
это 100%, находим 90%
2663,325-------------------100%
х---------------------------------90%
х=2663,325*90/100=2397гр
1)<span>CH4><span>C2H2><span><span>C2H4>(ты уверена,что не хлорэтил)? <span>C2H5Cl><span>CH3CH2OH</span></span></span></span></span></span>
<span><span><span><span><span><span>CH4 = C + 2 H2</span></span></span></span></span></span>
<span><span><span><span><span><span>C2H2 = 2 C + H2</span></span></span></span></span></span>
<span><span><span><span><span><span>C2H4 = 2 C + 2 H2</span></span></span></span></span></span>
<span><span><span><span><span><span>CH3CH2OH = C2H4 + H2O</span></span></span></span></span></span>
<span><span><span><span><span><span>2)<span>С</span>2<span>H</span>5<span>OH>не знаю> не знаю>C4H9OH</span></span></span></span></span></span></span>
1.Нуклеофильные: б),в)д)
Электрофильные: г)е)а)
2. <span>а)
3.б)
4.б)
5.б)
6.в)
7.б)
8.1 род:OH,CH3,Cl
2 род: COOH, NO2,SO3H</span>
1.
3N2 + 3H2 = 2NH3
2Mg + O2 = 2MgO
Cl2 + H2 = 2HCl
3Mg + N2 = Mg3N2
2Na + O2 = Na2O2
2.
4Li + O2 = 2Li2O
H2 + Br2 = 2HBr
CuO + SO2 = CuSO3
2H2 + O2 = 2H20
K2O + CO2 = K2CO3
3.
2H20 = O2 + 2H2
Cu(OH)2 = CuO + H20
H2CO3 = CO2 + H2O
CaCO3 = CaO + CO2
Ca(HCO3)2 = CaCO3 + CO2 + H2O