1) 4, 10
2)4, -8, 0, 10, -42
3)4, 1/3, 6,8, 12 целых 4/9, 10,
4) -8, -42
5)1/3, 6,8, 12 целых 4/9
а/b=3,5
3,5b=а
b/(4а+7b)=b/4(3,5b)+7b=b/21b=1/21
<span>2cos3x = √3 </span>
<span>cos3x = √3 / 2 </span>
<span>3x = arccos(√3 / 2) + 2πk, k є Z </span>
<span>3x = ±π/6 + 2πk, k є Z </span>
<span>x = ±π/18 + 2πk, k є Z</span>