Question

Помогите, пожалуйста
1)log9^3 log2 8-log9^3 8
2)3/log3 2-2/log9 4-1/log27 8
3) loga 4*log8 a^2
4)(log по осн. корень из 3 от a+log9 a^2)/log81 a

Answer 1

2
log(9)4=log(3)2
log(27)8=log(3)2
3/log(3)2-2/log(3)2-1/log(3)2=0
3
log(a)4=2log(a)2
log(8)a²=2/3log(a)2
2log(a)2*2/3log(a)2=4/3
4
log(√3)a=2log(3)a
log(9)a²=log(3)a
log(81)a=log(3)a/4
(2log(3)a+log(3)a):log(3)a/4=3log(3)a*4/log(3)a=12