1смена -3•9=27
2 смена-4•10=40
40-27=13
12-4= 8 ябл
8:2=4 ябл в каждой вазе поровну
4+1=5 ябл в 1 вазе
4+3=7 ябл во 2 вазе
2 1/3:1 5/9 =2 3/5
2 3/5 - 5/6= 1 48/30 - 25/30 = 1 23/30
8+8*8=8*8=64+8=72,т.к. первое умножение(*)
<span>|x + 6| - |4x - 5| = 15
x < - 6
-x - 6 + 4x - 5 = 15
3x - 11 = 15
3x = 26
![\left \{ {{x\ \textless \ -6} \atop {x=\frac{26}{3} }} \right.](https://tex.z-dn.net/?f=+%5Cleft+%5C%7B+%7B%7Bx%5C+%5Ctextless+%5C+-6%7D+%5Catop+%7Bx%3D%5Cfrac%7B26%7D%7B3%7D+%7D%7D+%5Cright.+)
x ∈ ∅
-6 ≤ x < 5/4
x + 6 + 4x - 5 = 15
5x + 1 = 15
5x = 14
![\left \{ {{-6 \leq x\ \textless \ \frac{5}{4} } \atop {x= \frac{14}{5} }} \right.](https://tex.z-dn.net/?f=+%5Cleft+%5C%7B+%7B%7B-6+%5Cleq+x%5C+%5Ctextless+%5C++%5Cfrac%7B5%7D%7B4%7D+%7D+%5Catop+%7Bx%3D+%5Cfrac%7B14%7D%7B5%7D+%7D%7D+%5Cright.+)
</span><span>x ∈ ∅
</span>
<span>x ≥ 5/4
x + 6 - 4x + 5 = 15
11 - 3x = 15
3x = -4
![\left \{ {{x \geq \frac{5}{4} } \atop {x=- \frac{4}{3} }} \right.](https://tex.z-dn.net/?f=+%5Cleft+%5C%7B+%7B%7Bx+%5Cgeq++%5Cfrac%7B5%7D%7B4%7D+%7D+%5Catop+%7Bx%3D-+%5Cfrac%7B4%7D%7B3%7D+%7D%7D+%5Cright.+)
</span>x ∈ ∅
Уравнение не имеет решений: <span>x ∈ ∅.</span>