дано
m(C2H5OH) = 4.6 g
m(ppa Ba(OH)2) = 540 g
W(Ba(OH)2) = 10%
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m((C2H5O)2Ba)-?
m(Ba(OH)2) = 540*10% / 100% = 54 g
M(C2H5OH) = 46 g/mol
n(C2H5OH) = m/M = 4.6 / 46 = 0.1 mol
M(Ba(OH)2) = 171 g/mol
n(Ba(OH)2) = m/M = 54 / 171 = 0.32 mol
n(C2H5OH) < n(Ba(OH)2)
2C2H5OH+Ba(OH)2-->(C2H5O)2Ba+2H2O
2n(C2H5OH) = n((C2H5O)2Ba)
n((C2H5O)2Ba) = 0.1 / 2 = 0.05 mol
M((C2H5O)2Ba) = 227 g/mol
m((C2H5O)2Ba) = n*M = 0.05 * 227 = 11.35 g
ответ 11.35 г
1.PH3+Cl2=PCl3+2HCl
2.CH4+Cl2=CCl4+2HCl
3.2P+N2O=N2+P2O5
4.Na+H2O=H2+NaOH
Реакции находятся на фото
1) 2Сr+6HCL=2CrCl3 + 3H2
2) CrCl3+3NaOH(конц)=Cr(OH)3 + 3NaCl
2) 2Cr(OH)3=Cr2O3 + 3H2O(протекает при повышении температур t*)
4) Cr2O3 + 2Al = Al2O3 + 2Cr