Question

sin(-7п) +2cos(31п/3)-tg(7п/4)

Answer 1

$sin(-7 \pi )+2cos( \frac{31 \pi }{3} )-tg( \frac{7 \pi }{4} )=\\\\ =-sin(6 \pi + \pi )+2cos(10 \pi + \frac{ \pi }{3} )-tg( 2 \pi -\frac{ \pi }{4} )=\\\\ =-sin \pi +2cos\frac{ \pi }{3}+tg\frac{ \pi }{4} =0+2\cdot \frac{1}{2} +1=1+1=2$