у=lg(4x²+11x)
ООФ: 4х²+11х>0 + + + - - - - - + + + +
х(4х+11)>0 -----------(-11/4)------------(0)----------------
х∈(-∞, -11/4)∨(0,+∞)
124200
121904
28700
23040
188100
262800
81160
301560
17600
176
300
528000
528005280
Ответ:
1) х+10=12, х=12-10=2; 2)28у=60+24,у=84:28=3; 3) z=32+15=47; 4)11t=0+33. 5)x+59=86*42=(86*42)-59; 6)528:k=64+24, k=528:88=6
7/16 - 5/24 = 42/96 - 20/96 = 22/96 = 11/48
12/13 - 15/26 = 24/26 - 15/26 = 9/26
39/40 - 19/28 = 273/280 - 190/280 = 83/280