1)AlBr3+HOH=AlOHBr2+HBr
Al(3+) +3Br(-) +HOH=AlOH(2+) +2Br(-) +H(+) +Br(-)
<span>Al(3+) +HOH=AlOH(2+) +H(+)
2)</span>FeCl2<span> + HOH ↔ FeOHCl + HCl</span>
Fe2+<span> + 2Cl</span>-<span> + H</span>2O ↔ FeOH+<span> + Cl</span>-<span> + H</span>+<span> + Cl</span>-
Fe2+<span> + H</span>2O ↔ FeOH+<span> + H</span><span>+
3)</span> CuSO4<span> + 2H</span>2O = Cu(OH)2<span> + H</span>2SO4
Cu2+<span> + SO</span>42-<span> + 2H</span>2O = Cu(OH)2<span> + 2H</span>+<span> + SO</span>4<span>2-
4)</span><span>KNO2 + H2O = KOH + HNO2 </span>
<span>K+ + NO2- + H2O = K+ + OH- + HNO2 </span>
<span>NO2- + H2O = OH- + HNO2</span><span>
</span>
<span>WO3+3H2 ========= 3H2O+W </span>
2Mg+O2→2MgO
MgO + 2HNO3→Mg(NO3)2 + H2O
Mg(NO3)2 + 2NaOH→Mg(OH)2 + 2NaNO3
Правельный ответ 2, так как S меняет с -2 до 0 ( т.к. чистое вещество)
(NH4)2S+Cu(NO3)2=2NH4NO3 + CuS