<span>P</span><span>2</span><span>O</span><span>5 --------------><span> </span><span>Na</span><span>3</span><span>P</span><span>О4 ------><span>H</span><span>3</span><span>PO</span><span>4</span></span></span>
3Cu+8HNO3--3Cu(NO3)2+2NO+4H2O
n(Cu(NO3)2)=120:188=0,64(МОЛЬ)
n(Cu)=n(Cu(NO3)2)=0.64МОЛЬ
.............................
2) M(KCl)=39+35,5=74.5 г\моль
m(KCl)= 1.5 моль * 74,5 г\моль= 111, 75 г