Mg*sin(α)-mg*sin(α)<=Mg*cos(α)*μ+mg*cos(α)*<span>μ
</span>mg*sin(α)-Mg*sin(α)<=Mg*cos(α)*μ+mg*cos(α)*μ
*****************************************************
(M-m)*sin(α)<=(M+m)*cos(α)*μ
(m-M)*sin(α)<=(M+m)*cos(α)*μ
*****************************************************
(M-m)*tg(α)<=(M+m)*μ
(m-M)*tg(α)<=(M+m)*μ
*****************************************************
M*(tg(α)-μ)<=m*(μ+tg(α))
m*(tg(α)-μ)<=M*(μ+tg(α))
*****************************************************
M*(1-0,2)<=m*(0,2+1)
m*(1-0,2)<=M*(0,2+1)
*****************************************************
M*0,8<=m*1,2
m*0,8<=M*1,2
*****************************************************
M*2/3<=m
m<=M*1,5
*****************************************************
M*2/3 <= m <= M*1,5
Т.к. удельная теплоемкость воды самая большая и тепло удерживает вода больше воздуха
4,5 т = 4500 кг; 0,75 т = 750 кг; 4000г = 4 кг; 120г = 0,12 кг; 25 кг = 0,025 кг.
P1=m1*g/S1=ro1*V*g/S1
p2=(m1+m2)*g/S2=(m1+m2)*g/(2*S1) = (ro1+ro2)*V*g/(2*S1)
*********
p1=ro1*V*g/S1
p2=(ro1+ro2)*V*g/(2*S1)
**********
p1/p2=ro1*V*g/S1 : (ro1+ro2)*V*g/(2*S1) = ro1 : (ro1+ro2)/2 =2*ro1/(ro1+ro2)
p1/p2=2*ro1/(ro1+ro2)
p1=p2*2*ro1/(ro1+ro2)=7590*2*1400/(1400+7800) Па = <span>
2310 Па - это ответ
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