1-вопрос:1
2-вопрос:
H2NCH2COOH+HBr=[H3NCH2COOH]Br (комплексная соединение)
3- тоже самая
4-вопрос:
1)C2H5COOH+C3H7OH=
=C2H5COOC3H7+H2O
2)C4H9COOH+CH3OH=
=C4H9COOCH3+H2O
6)CH3COOH+C4H9OH=
=CH3COOC4H9+H2O
Ω% = m в-ва*100%/m р-ра
m в-ва = ω%*m р-ра/100% = 10*150/100 = 15 г
12 = (15 + х)*100/(150 + x)
12*(150 + x) = (15 + х)*100
1800 + 12x = 1500 + 100x
88x = 300
x = 3,41 г (нужно добавить)
C2H4+HBr->C2H5Br
C2H4->C2H2+H2
3C2H2->C6H6
2C6H6+15O2->12CO2+6H2O
C6H6+HNO3->C6H5NO2+H2O
C6H6+3CL2->C6H6Cl6
<span>Mr(H203) = H2 + O3= 1*2 + 16*3 = 2 + 48 = 50 </span>