A) a = -1, ветви - вниз
Б) a = 1, ветви - вверх
В) a = -1, ветви - вниз
Б - 2
Подставим x = 1 в первое уравнение, получим
y = -1 + 2 + 5 = 6, Соответствует графику 1
Ответ:
1 2 3
3x-2*x^2=0x=0 или 3-2*x=0
x=0 или х=3/2
А)<span><span>(<span><span>x2</span>+x</span>)</span><span>(<span>49−<span>x2</span></span>)</span>=</span>Раскрытие скобок:<span><span>x2</span>49+<span>x4</span><span>(<span>−1</span>)</span>+x49+<span>x3</span><span>(<span>−1</span>)</span>=</span><span>49<span>x2</span>−<span>x4</span>+49x−<span>x3</span>=</span><span>−<span>x4</span>−<span>x3</span>+49<span>x2</span>+49x</span>Ответ: <span>−<span>x4</span>−<span>x3</span>+49<span>x2</span>+49x
В)</span><span><span>(<span><span>x2</span>−7</span>)</span><span>(<span><span>x2</span>+18</span>)</span>=</span>Раскрытие скобок:<span><span>x4</span>+<span>x2</span>18−7<span>x2</span>−126=</span><span><span>x4</span>+11<span>x2</span>−126</span>Ответ: <span><span>x4</span>+11<span>x2</span>−126
Д)</span><span><span>(<span><span>x2</span>−3<span>x2</span></span>)</span><span>(<span><span>x2</span>+7</span>)</span>=</span>Приведение подобных:<span><span>(<span>−2<span>x2</span></span>)</span><span>(<span><span>x2</span>+7</span>)</span>=</span>Раскрытие скобок:<span>−2<span>x4</span>−14<span>x2</span></span>Ответ: <span><span>−2<span>x4</span>−14<span>x2
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Вроде так, но я могла где-то накосячить
