<span>N2</span><span>+ </span><span>3</span><span>H</span>2<span> = 2NH</span>3
<span>4</span><span>NH3</span><span> + 5O</span>2<span> = 4NO + 6H</span>2<span>O</span>
<span>2</span><span> </span><span>N</span><span>O + O</span>2<span> = 2NO</span>2
<span>4</span><span>NO2</span><span> + O</span>2<span> + 2H</span>2<span>O</span>(гор.)<span> = 4HNO</span>3(конц.)
<span>2</span><span>HNO3</span><span> + </span><span>C</span><span>a</span><span>O = Ca(NO</span>3<span>)</span>2<span> + H</span>2<span>O</span>
<span>23+16+1)*100/(78+23-1)=40*100/100=40%</span>
D(N2)(вещества)=Mr(вещества)/Mr(N2)
Mr(вещества)=D(N2)(вещества)*Mr(N2)=1.57*28=43.96
Ответ:Mr(Вещества)=43.96