M(H2S) = m(H2S)/n(H2S) >> m(H2S) = n•M
M(H2S) = 2•1 + 32 = 34
m(H2S) = 0,4 • 34 = 13,6г
2,2,3,4-тетраметилдеканол-4
Вторая схема, если актуально
3моль 4моль
3Fe+4H2O(t) =Fe3O4+4H2
3 4
n(Fe)=168/56=3моль; n(H2)=3*4/3=4моль; V(H2)=4*22,4=89,6л.
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