а) F(x) = 2 -5x, G(x) = x^4
б) F(x) = tgx, G(x) = <span>sqrt </span>x
С осью ОУ
<em>х=0 у=3</em>
с осью ОХ
<em>у=0 </em> 0=-0,8х+3 <em> х=3,75</em>
Решение:
(х-1)(х-2)(х+3)-(х+1)(х+2)(х-3)=(x²-2x-x+2)(x+3)-(x²+2x+x+2)(x-3)=(x²-3x+2)(x+3)-(x²+3x+2)(x-3)=(x³+3x²-3x²-9x+2x+6)-(x³-3x²+3x²-9x+2x-6)=(x³-7x+6)-(x³-7x-6)=x³-7x+6-x³+7x+6=12