1 дм^3 = 1 л
V(NH3) = 8.2 л
NH4Cl + Ca(OH)2 = <span>CaCl2 + 2NH3 + 2H2O
n(NH4Cl) = m/M = 20 г / 53,5 г|моль = 0,3738 моль
n(NH3) = 2n(NH4Cl) = 0,7476 моль
Vтеор(NH3) = n*Vm = 0,7476 моль * 22,4 л|моль = 16,74624 л
Виход = Vпрак / Vтеор = 8.2 л / 16,74624 л = 0, 48966 = 48.966%</span>
A) ZnO+H2SO4=ZnSO4+H2O
ZnSO4+2NaOH=Na2SO4+Zn(OH)2
Zn(OH)2+2NaOH=Na2ZnO2+2H2O
Na2ZnO2+4HCl=2NaCl+ZnCl2+2H2O
б) 2Zn+O2=2ZnO
ZnO+N2O5=Zn(NO3)2
Zn(NO3)2+Na2CO3=ZnCO3+2NaNO3
ZnCO3+2HCl=H2O+CO2+ZnCl2
1)n(NaOh)=
![\frac{m(NaOh)}{M(NaOH)}](https://tex.z-dn.net/?f=+%5Cfrac%7Bm%28NaOh%29%7D%7BM%28NaOH%29%7D++)
M(NaOH)=23+16+1=40г/моль
n(NaOH)=
![\frac{16}{40}](https://tex.z-dn.net/?f=+%5Cfrac%7B16%7D%7B40%7D++)
=0.4моль
2)n(CO2)=
![\frac{V(CO2)}{Vm}](https://tex.z-dn.net/?f=+%5Cfrac%7BV%28CO2%29%7D%7BVm%7D+)
Vm=22.4г/моль
n(CO2)=
![\frac{44.8}{22.4}](https://tex.z-dn.net/?f=+%5Cfrac%7B44.8%7D%7B22.4%7D+)
=2моль
m(CO2)=n(CO2)*M(CO2)
M(CO2)=12+16*2=44г/моль
m(CO2)=2моль*44г/моль=88г