Question

Номер 913 пожалуйста.помогите,очень срочно

Answer 1

А)$(1 \frac{11}{18}+ \frac{13}{24}-1 \frac{13}{36})* 1\frac{3}{5}=(\frac{29}{18}+ \frac{13}{24}- \frac{49}{36})* \frac{8}{5}=( \frac{116}{72} + \frac{39}{72} - \frac{98}{72} )* \frac{8}{5}=$$\frac{57}{72} * \frac{8}{5}= \frac{57*8}{72*5}= \frac{57}{9*5}= \frac{57}{45}=1 \frac{12}{45}=1 \frac{4}{15}$
б)$\frac{14}{15} *1 \frac{3}{7} + \frac{7}{10} * \frac{3}{14} = \frac{14}{15}* \frac{10}{7}+ \frac{7}{10}* \frac{3}{14}= \frac{14*10}{15*7} + \frac{7*3}{10*14} = \frac{4}{3}+ \frac{3}{20}=$$\frac{80}{60}+ \frac{9}{60} = \frac{89}{60}= 1 \frac{29}{60}$