<span>(x-7)²≤√11*(x-7)
</span>(x-7)²-√11*(x-7)≤0
(x-7)(x-7-√11)≤0
x₁=7 x₂=7+√11
-∞___ + ___ [7] ___ - ___ [7+√11]___ + ___ +∞
x∈[7;7+√11]
= (10-2,6t^6)^2 = 10^2 - 2*10*2,6t^6 + (2,6t^6)^2 = 100-52t^6+6,76t^12
1) log2(64^(1/3)) = log2(4) = 2
2) (log4(2))^2 = (1/2)^2 = 1/4
3) log3(3^(1/8)) = 1/8 * log3(3) = 1/8
4) log2(1/8) = -3
5) 1/4 - 3 = -11/4
Применим данное соотношение
logn (b) * log m(c) = log m (b) * logn (c)
<span>log3 4*log2 3 = log2 4 * log3 3 = 2
</span>
log 1/4 (2) = - 1/2