Найти все частичные пределы последовательности an = sin(πn/4)*|cos(πn/3)|^n
1)1/6x^2 = 2/12х² <span>
1/4х =</span> 3х/12х²<span>
</span><span>2)1/3х^2у= 12у</span>²/36х²у³<span>
1/12ху^2 = 2ху/36х</span>²у³<span>
1/18х^2у^3 = 2х</span>²/36х²у³<span>
3)1/(х+у)^2 = (х +у)/(х+у)</span>³<span>
1/(х+у)^3
4)1/(а-b)
1/(b-а) = -1/(а - b)
5)1/4х^2-1 и 1/1+2х
1/4х</span>² -1
(2х -1)/(4х² -1)