Question

lim x->0 x/ √3+x -√3-x lim x->4 2-√x/3-√2x+1 lim x -> к бесконечности 5x4-x3+2x/x4-8x3+1

Answer 1

=lim(x->беск (x^2(3+5/x-7/x^2)) / (x^2(3+1/x+1/x^2))=(3+0-0)/3+0+0) = 3/3 = 1