<span>1)H2CO3
2)</span><span>CO2
3)</span><span>2NH
4)</span><span>H2SO4
5)</span>S<span> + </span>O<span>2 = </span>SO<span>2 У о - постоянная 2, у s - получается 4 </span>
2CH3OH + 3O2=2CO2 + 4H2O
n(CH3OH)=m/M=100/32=3.125 моль
n(CH3OH)/2=n(O2)/3
n(O2)=4.7 моль
V(O2)=4.7*22.4=105.3 л
V(возд)=105.3:0.21=501.4 л