KekLoLArbidol
1. 2Ba+O2=2BaO
2.BaO+H20=Ba(OH)2
3.3Ba(OH)2+2H3PO4=Ba3(PO4)2 +4H2O
4. 4P+5O2=2P2O5
5.P2O5+3H2O=2H3PO4
Первым ставится элемент в формуле тот, у которого электроотрицательность больше
Na2O(+1,-2)
Na2O2(+1,-1)
FeO(+2,-2)
Fe3O4...Fe2O3×FeO(+3,-2)×(+2,-2)
FeS(+2,-2)
H2SO4(+1,+6,-2)
<span><span>H3PO4+3KOH</span> = K3PO4</span><span> + 3H2O</span>
<span><span>H3PO4+3Na2O= <span>3H2O</span><span>+2Na3PO4</span></span></span>
<span><span><span><span>2K3PO4+3MgCl2=6KCl+Mg3(PO4)2</span></span></span></span>
<span><span><span><span><span>H3PO4+3AgNO3=3HNO3+Ag3PO4</span></span></span></span></span>
m(раствора)=100+10=110г
w2=(100*0,21+10)/110=0,282