<span>y" − 2y′+ 10y = 0
линейное однородное ДУ 2 порядка
</span>
<span>k^2− 2k+ 10 = 0
d=4-40=-36
k1=1+3i
k2=1-3i
</span>y(x)=e^x*(С1*sin(3*x)+С2*cos(3*x))
y(0)=e^0*(С1*sin(0)+С2*cos(0))=1*(С1*0+С2*1)=C2=3
y(x)=e^x*(C1*sin(3*x)+3*cos(3*x))
y`(x)=e^x*(C1*sin(3*x)+3*cos(3*x))+e^x*(3*C1*cos(3*x)-9*sin(3*x))
y`(0)=e^0*(C1*sin(3*0)+3*cos(3*0))+e^0*(3*C1*cos(3*0)-9*sin(3*0))
y`(0)=3+3*C1=0
C1=-1
y(x)=e^x*(-sin(3*x)+3*cos(3*x))
1)(-36*9):((-6)+3)
(-324):(-3)=-108
2)(-80*-45):(-8+3)
(-125):(-5)=-25
47*0.01=0.47
0.47+2=2.47
2*0.01=0.02
0.02-4= - 3.98
8а=8*0.01=0.08
1.а) 24:(6 (-7)+40)
24÷(-42+40)
24÷(-2)
=-12
Б. 36×2.9-16×2.9
2.9 (36-16)
2.9×20
=58
В.не знаю
3.38-3 (x-2)-x
38-3x+6-x
=44-4x