S''(t)=a(t)
S''(t)=(4t^3/3-5t+12)''=(12t^2-5+0)'=24t=24*3=72
Или если t^3 внизу
S''(t)=(4/3*t^-3-5t+12)''=(-4*t^-4-5)'=16/t^5=16/243=0,065
Y = (x - 7)/(2x + 4)
2x + 4 ≠ 0
2x ≠ - 4
x ≠ - 2
D (y) = ( - ω; - 2) ∨ ( - 2; + ω)
1)7х^2 - 4х - 24 + х^2 = 0
8х^2 - 4х - 24 = 0
4 (2х^2 - х - 6) = 0
2х^2 - х - 6 = 0
2х^2 - х - 4 - 2 = 0
2(х^2-1) - х - 4 = 0
х^2 -1 - х - 4 = 0
х^2 - х - 5 = 0
х(х-1) - 5 = 0
х-1-5=0
х = 6
2)7 - 6х - 3 = 10
7 - 6х = 13
6х = -6
х = -1
3)6-5х=7
5х = -1
х = -0,2
X=5-2y
2(5-2y)+y=9
10-4y+y=9
1=3y
y=1/3
x=5-2/3
x=13/3
x=4,1/3
<span>2 sin x + sin² x + cos² x =1
2 sin x+1=1
sin x=0
x=</span>πN