Для них не характерны реакции присоединения
<span><span>2Fe</span>+<span>6<span>HCl</span></span> → <span>3<span>H2</span></span>+<span>2<span>FeCl3
</span></span></span><span><span>FeCl3</span>+<span>3<span>H2O</span></span> → <span>3<span>HCl</span></span>+<span>Fe<span>(OH)</span>3
</span></span><span><span>2<span>Fe<span>(OH)</span>3</span></span> → <span>Fe2O3</span>+<span>3<span>H2O
</span></span></span><span><span>2<span>Fe2O3</span></span> → <span>4Fe</span>+<span>3<span>O2
</span></span></span><span>Fe+<span>H2SO4</span> → <span>FeSO4</span>+<span>H2
</span></span><span><span>FeSO4</span>+<span>2<span>NaOH</span></span> → <span>Fe<span>(OH)</span>2</span>+<span>Na2SO4
</span></span><span><span>Fe<span>(OH)</span>2</span> → <span>H2O</span>+<span>FeO
</span></span><span><span>2<span>FeO</span></span> → <span>2<span>Fe</span></span>+<span>O<span>2</span></span></span>
Пишем реакцию
C2H4 + H2 = C2H6
Считаем количество вещества этана
n = m / M = 300 / 30 = 10 моль
По уравнению этилена столько же, т.е. 10 моль
Считаем его объем
V = n * Vm = 10 * 22.4 = 224 л