<span>9-25-41-57-73-89-105-121 будет так)*=Р</span>
F(11) = F(10) + F(9) = F(9) + F(8) + F(8) + F(7) = F(8) + F(7) + F(8) + F(8) + F(7) = 3F(8) + 2F(7)
7 = 3F(8) + 4 => F(8) = 1.
F(8) = F(7) + F(6) <=> F(6) = F(8) - F(7) = 1 - 2 = -1.
F(7) = F(6) + F(5) <=> F(5) = F(7) - F(6) = 2 - (-1) = 3.
F(6) = F(5) + F(4) <=> F(4) = F(6) - F(5) = -1 - 3 = -4.
F(5) = F(4) + F(3) <=> F(3) = F(5) - F(4) = 3 - (-4) = 7.
1*10⁴+4*10³+6*10² может не точно, проверь если что)
Program math;var a: real;var i,n: integer;begina:=1;readln(n);for i:=1 to n dobegin a:=a+(1/i);end;writeln(a);end.
75 | 16
64 |----- 75 (10cc) =4B (16cc) =100 1011 (2cc) =113 (8cc)
---- | 4
11