Question

Упростите(m^2-n^2/m-n)- (m^3-n^3\m^2-n^2)

Answer 1

$\frac{m^2-n^2}{m-n}-\frac{m^3-n^3}{m^2-n^2}=\frac{(m-n)(m+n)}{m-n}-\frac{(m-n)(m^2+mn+n^2)}{(m-n)(m+n)}=$

$=(m+n)-\frac{m^2+mn+n^2}{m+n}=\frac{(m+n)^2-(m^2+mn+n^2)}{m+n}=$

$=\frac{m^2+2mn+n^2-m^2-mn-n^2}{m+n}=\frac{mn}{m+n}$