Question

Помогите с уравнением

Answer 1

$\frac{ x^{2}+x}{x+3} - \frac{6}{3+x} =0 \\ \frac{ x^{2}+x-6 }{x+3} =0 \\ x \neq -3 \\ x^{2} +x-6=0 \\ D=1-4*(-6)=25 \\ \sqrt{D} = \sqrt{25} =5 \\ x_{1} = \frac{-1-5}{2} =- \frac{6}{2} =-3 \\ x_{2} = \frac{-1+5}{2} =\frac{4}{2}= 2$