Sin(a+2a)-cosasin2a=sinacos2a+sin2acosa-cosasin2a=sinacos2a
3x-x>3x+5
3x-3x-x>5
-x>5
x<-5
Ответ: х<-5
⁴√(11-√40) * ⁴√(√40 +11) = ⁴√(11² -(√40)²) = ⁴√(121-40) = ⁴√81 =
= ⁴√3⁴ = 3
Х=4+у
(4+у)^2+y(4+y)=6
х=4+у
16+8у+у^2+4у+у^2=6
х=4+у
2y^2+12y+10=0
х=4+у
y2+6y+5=0
D=36-4*5=36-20=16
y1=(4-6)/2=-1
y2=(-4-6)/2=-5
x1=4-1=3
x2=4-5=-1
y1=-1
y2=-5