Дано:
<span>ω</span><span>(</span><span>C</span><span>) </span>= <span>52.18</span>%
<span>ω</span><span>(</span><span>H</span><span>) = 1</span><span>3.04</span><span>%</span>
<span>ω</span><span>(</span><span>O</span><span>) = </span><span>34.78</span><span>%</span>
Найти:
Установить формулу-?
Решение:
<span>n</span><span>(</span><span>C</span><span>) : </span><span>n</span><span>(</span><span>H</span><span>) : </span><span>n</span><span>(</span><span>O</span><span>) = 52.18/12 : 13.04/1 : 34.78/16</span>
<span><span> </span><span> </span><span> </span>4.35 : 13.04 : 2,17</span>
<span><span> </span>2 : 6 : 1</span>
<span>C</span><span>₂</span><span>H</span><span>₆</span><span>O</span>
Ответ: <span>C</span><span>₂</span><span>H</span><span>₆</span><span>O</span>
M3 = Vxp = 10000x1,2 = 12000 г = 12 кг
m3 = m1 + m2 = V1xp1 + V2xp2 = m1 + (m3 - m1)
W3m3 = W1m1 + W2m2 = W1V1p1 + W2V2p2
12x27 = 60xm1 + 14(m3 - m1) = 60xm1 + 14m3 - 14m1 = 46m1 + 14x12
324 = 46m1 + 168
46m1 = 324 - 168 = 156
m1 = 156/46 = 3,39 кг
m2 = m3 - m1 = 12 - 3,39 = 8,61 кг
V1 = m1/p1 = 3390/1,5 = 2260 мл = 2,26 л
V2 = m2/p2 = 8610/1,1 = 7827 мл = 7,827 л
Ответ:
O2 - ковалентно неполярная
BaO- ионная
Na2S - ионная
Объяснение:
эмммм я тут не причём я в 6 классе я малолетка =D
<span>NaOH+H2SO4=NaHSO4+H2O
+ - + 2- + + 2-
Na + OH + 2H + SO4= Na + H + SO4 + H2O полное
</span> - +
OH + H=H2O сокращённое
