Да, получится дифторид кислорода( OF2)
<span>2C6H5OH + 2K = 2C6H5OK + H<span>2</span></span>
1)С4H8+HBr->C4H9Br
2)C4H9Br+KOH(водн.)->С4H9OH+KBr
3)C4H9OH+CuO-t>C3H7COH+Cu+H2O
4)C3H7COH+Ag2O=2Ag+C3H7COOH
5)C3H7COOH+KOH=C3H7COOK+H2O
H2O<span> + </span>SO2<span> = </span>H2<span>SO3
</span>N2O5<span> + </span>H2O<span> = 2HNO3</span>