Question

Решить уравнение (2х+4)*20-85=35, 32+(136-х*8):4=64

Answer 1

$(2x + 4) \times 20 - 85 = 35 \\ 40x + 80 = 35 + 85 \\ 40x = 35 + 85 - 80 \\ 40x = 40 \\ x = 40 \div 40 \\ x = 1$

Ответ: 1.
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$32 + (136 - 8x) \div 4 = 64 \\ 32 + 34 - 2x = 64 \\ 66 - 2x = 64 \\ - 2x = - 2 \\ x = - 2 \div ( - 2) \\ x = 1$

Ответ: 1.