Question

0,08 моль ?)))))))))))))))

Answer 1

N(Al2S3) = 1/2 n (Al) = 1/2 m(Al)/M(Al) = 1/2 * 4,5/27 = 0,083 моля
M(Al2S3) = 27*2 + 32*3 = 150 г/моль
m(Al2S3) = n(Al2S3)*M(Al2S3) = 150 * 0,083 = 12,5 г