Ответ☆☆☆☆☆☆☆☆☆☆☆☆-----------
2^3=2^ (2*(x/2+1)
3=x+2
x=1
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4x-y=11
6x-2y=13
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y=4x-11
6x-2(4x-11)=13
6x-8x+22=13
-2x=13-22
-2x=-9, x=9/2, x=4,5
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y=4.4,5-11, y=18-11,y=7
/x,y/=/4,5, 7/
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11)a²y²-x⁶=(ay-x³)*(ay+x³)
12)c²-6c+9-4x²=(-4)x²+c²-6c+9=-(2x-c+3)*(2x+c-3)