Question

Решите уравнение x^2 + 4x - 8=0

Answer 1

X^2+4x-8=0
D=4^2-4*(-8)=16+32=48
x1=-4+48/2=22
x2=-4-48/2=26

Answer 2

$x^2+4x-8=0\\\\ a = 1, \ b = 4, \ c = -8 \\\\ D= b^2 - 4ac=16+4\cdot8=16+32=48 \\\\ x_{1,2}=\cfrac{-b \pm \sqrt{D}}{2a}=\cfrac{-4 \pm \sqrt{48}}{2}=\cfrac{-4 \pm 4\sqrt3}{2}=-2\pm 2\sqrt3$

Ответ: $-2\pm 2\sqrt3$