Y=f'(1)(x-1)+f(1)
f'=2x/(1+x^2)
f'(1)=2/2=1
f(1)=ln(2)
y=x-1+ln2
Ответ:
Пошаговое объяснение:
1) -2/9 + ( 8/36 - 27/36 ) = - 2/9 - 19/36 = - 8/36 - 19/36 = - 27/36 = -3/4 = -0,75
2) 4/7 - ( 35/77 - 33/77 ) = 4/7 - 2/77 = 44/77 -2/77 = 42/77 = 6/11
3) 3 5/6 + ( - 35/42 - 6/42 ) = 23/6 - 41/42 = 151/42 - 41/42 = 110/42 = 55/21 = 2 13/21 ( на счет этого сомнения )
4) 3/8 - ( 8/72 - 45/72 ) = 3/8 + 37/72= 21/72 + 37/72 = 29/36
5) 2 3/4 - (5/4 + 11/2 ) = 2 3/4 - ( 5/2 + 22/4) = 11/4 - 27/4 = -4
6) 53/8 - ( 7/4 - 19/8 ) = 53/8 - (14/8 - 19/8 ) = 53/8 + 23/8 = 76/8 = 38/4 = 19/2 = 9 1/2 = 9,5
7x=-95,4-2x;
7x+2x=-95,4;
9x=-95,4;
x=-95,4:9;
x=-10,6
V(t)=S'(t)
S'(t)=-1/6*3*t^2+7/2*2*t-1=-1/2*t^2+7*t-1
a(t)=0
a(t)= V'(t)=-1/2*2*t+7=t+7
-t+7=0
-t=-7
t=7c