Ba²⁺+CO₃²⁻+2H⁺+2Cl⁻⇒Ba²⁺+2Cl⁻+H₂O+CO₂
2Ag⁺+2NO₃⁻+Mg²⁺+2Cl⁻⇒2AgCl+2Mg²⁺+2NO₃⁻
Fe²⁺+SO₄²⁻+2H⁺+2Cl⁻⇄Fe²⁺+2Cl⁻+2H⁺+SO₄²⁻
Fe³⁺+3NO₃⁻+3Na⁺+3OH⁻⇒Fe(OH)₃+3Na⁺+3NO₃⁻
W(X) = 100%*m(X)/m, m = p*V => m(X) = w(X)*p*V/100%
m(X) = 10%*1,2*20/100% = 2,4 г
Ответ: 2,4 г