√2*(√50-<span>√32)
</span>√2*(5√2-4<span>√2)
</span>√2*(<span>√2*(5-4))
</span>√2*(<span>√2*1)
</span>√2*<span>√2 =2 </span>
10x²-3x-4=0D=b²-4ac D=b²-4ac D=-3²-(4*10*(-4))=9+160=169
a=10, b=-3, c=-4
x1,2=-b+-√D / 2a x1=3-13/20=-10/20=1/2 x2=3+13/20=16/20=4/5