Question

Решите : (1/3-1/2)в квадрате ×(-1/2)в кубе

Answer 1

$( \frac{1}{3} - \frac{1}{2} )^2*(- \frac{1}{2} )^3=( \frac{2}{6} - \frac{3}{6} )^2*(- \frac{1}{8} )=(- \frac{1}{6} )^2*(- \frac{1}{8} )= \frac{1}{36}*(- \frac{1}{8})=$$=- \frac{1}{288}$