2( Х - 3 ) - 1 > 3( Х - 2 ) - 4( Х + 1 )
2х - 6 - 1 > 3х - 6 - 4х - 1
2х - 7 > - Х - 7
3х > 0
Х > 0
( 0 ; + бесконечность)
-0,2x³-3x-4x²
-0,2x³-4x²-3x
y=-8/x y=2-x
-8/x=2-x ОДЗ: x≠0
-8=x(2-x)
-8=2x-
-2x-8=0
= 4
= -2
= -2
= 4
y=-8/x ∩ y=2-x = A (4;-2), B(-2;4)