<span>Подействовать спиртовым раствором щелочи</span>
Серебро Ag: заряд ядра +79, электронов 79, протонов 79, нейтронов 118
Дано:
m(HCl) = 14,6г
+Al
Найти:
m(Al)
Решение:
2Al + 6HCl = 2AlCl₃ + 3H₂
Mr(Al) = 27 г/моль (по реакции 54)
Mr(HCl) = 36,5 г/моль (по реакции 219)
m(Al) =
3,6г
Ответ: m(Al) = 3,6г
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