M(H2SO4) = 200 г*0,1 = 20 г
m"(p-pa H2SO4) = 200 г + 80 г = 280 г
ω"(H2SO4) = 20 г/280 г *100% = 7,14%
Ответ: 7,14%
N+7 )2)5
1s^2
2s^2,2p^3
P+15 )2)8)5
1s^2
2s^2,2p^6
3s^2,3p^3
K+19 )2)8)8)1
1s^2
2s^2,2p^6
3s^2,3p^6
4s^1
2HNO3+3H2S->2NO+3S+4H2O
3SO2+2KMnO4+4KOH->3K2SO4+2MnO2+2H2O
K+2H2O=H2+2KOH
FeCl3+3KOH=<span>Fe(OH)3 + 3KCl
Ca+2H2O=</span>Ca(OH)2 + H2
Cu(NO3)2+2NaOH=<span>Cu(ОН) 2 + 2NaNO3
a)
2Cu+O2=2CuO
CuO+H2O=Cu(OH)2
Cu(OH)2+2HCl=CuCl2+2H2O
б)
4Na+O2=2Na2O
Na2O+H2O=2NaOH
</span><span>NaOH + HCl = NaCl + H2O</span>