<span><span>3C + 4 HNO3 = 3CO2 + 4 NO+ 2 H2O
C - 4 e = C
N +3e = N
Доставляем до всех С 3, а где есть азот 4 и уравниваем </span></span>
CaO + 2 HNO3 = Ca(NO3)2 + H2O
KOH + HCl = H2O + KCl
Na2O + HSCu = CuO + HSNa2
Zn+H2SO4=H2+ZnSO4
Ca + 2 H2O = Ca(OH)2 + H2
Na2S + 2 HBr = H2S + 2 NaBr
2 KOH + CO2 = H2O + K2CO3
2 NaOH + SO3 = H2O + Na2SO4
<span>a) 4NH3+7O2=4NO2+6H2O</span>
<span>N+3 -1e- => N+4 1</span>
<span>O2 +2*2e- => 2O2- 4</span>
<span><span>b)2Al+3i2=2Ali3</span></span>
<span><span>Al -3e- => Al3+ 2</span></span>
i2 +2*1e- => 2i- 3
<span> c)5HNO3+3P+2H2O=3H3PO4+5NO </span>
N+5 +3e- => N+2 5
P -5e- => P+5 3
<span>d)<span>2</span><em>K</em><em>Mn</em><em>O</em>4<span> + </span><span>16</span><em>H</em><em>Cl</em><span> = </span><span>5</span><em>Cl</em>2<span> + </span><span>2</span><em>K</em><em>Cl</em><span> + </span><span>2</span><em>Mn</em><em>Cl</em>2<span> + </span><span>8</span><em>H</em>2<em>O</em></span>
<em>Mn+7 +5e- =>Mn+2 2</em>
<em>2Cl- -1*2e- =>Cl2 5</em>
N(NH3)=V/Vm=448л/22,4л/моль=20моль
m(NH3)n*M= 20моль*17г/моль=340г
m(раствор)=4,48+340=344,5г
W(NH3)=m(NH3)/m(раствор)=340г/344,5г=0,98 или 98%
1) CH3-COOH + C2H5OH -> CH3-COOC2H5 + H2O
Ответ: г - реакция этерификации
2) Ответ: г : 4-метилгексанол-2
3) Ответ: б - альдегидная
Прошу вас.