Question

Вычислить: 17, 2/3+4, 3/8-19, 5/9-(6, 1/36-5,3/16)=

Answer 1

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$17\frac{2}{3}+4\frac{3}{8}-19 \frac{5}{9} -(6 \frac{1}{36} -5 \frac{3}{16} ) = \frac{53}{3} + \frac{35}{8} - \frac{176}{9}- \frac{217}{36} + \frac{83}{16}$
$\frac{83}{16} + \frac{35}{8} = \frac{83}{16} + \frac{35*2}{8*2} = \frac{153}{16}$
$\frac{153}{16} + \frac{53}{3} = \frac{153*3}{16*3} + \frac{53*16}{3*16} = \frac{1307}{48}$
$- \frac{217}{36} - \frac{176}{9} =- \frac{217}{36} - \frac{176*4}{9*4} =- \frac{921}{36}$
$\frac{921}{36}|:3 = \frac{307}{12}$
$\frac{1307}{48} - \frac{307}{12} = \frac{1307}{48} - \frac{307*4}{12*4} = \frac{79}{48} =1 \frac{31}{48}$