1) friedel crafts acylation (CO + HCl+ AlCl3(cat.) ====> benzaldehyd
2) nitration (HNO3/H2SO4(cat.) ====> 3-nitro-m-benzaldehyd <---> 3-nitro-p-benzaldehyd
3)double wolf-kishner (N2H4 + KOH, t*)===> 3-amino-m/pbenzaldehyd (dynamic stability m- and p- form)
4)sandmeyer rxn I) NaNO2 + HCl II) H3O+ + t*-----> m- p- cresol
p-cresol + NaOH----> C7H7ONa (sodium cresol)
p-cresol + PCl5 -----> C7H6Cl + HCl + POCl3 (1-methyl-4-chlorobenzene
х моль 29.4 моль
N2 + <u>3H2</u> = <u>2NH3
</u> 3 моль 2 моль<u>
</u>n(NH3)=m/M=500 г / 17 г/моль =29.4 моль
х/3=29.4/2
х=44.1 моль (H2)
V(H2)=Vm*n=22.4 л/моль * 44.1 моль=987.84 л
Ответ: 987.84 л
Mr(Ca(NO2)2)=40+2*14+4*16=132
W(N2)=28/132=0.21=21%
<span>M=Mr=Ar(Н)*2+Ar(О) =1*2+16=18 г/моль</span>
<span>m = M *n = 18 г/моль * 5 моль = 90 г</span>
<span>M=Mr=Ar(Сu)+Ar(O) = 64+16 = 80 г/моль</span>
<span>m = M *n = 80 г/моль * 5 моль = 400 г</span>
<span>Масса СuО больше.</span>