2.даноm(p-pa)=29.2 gW(HCL)=5%MgSO3---------------------V(SO2)-?m(HCL)=29.2*5%/100%=1.46 g 1.46 X2HCL+MgSO3-->MgCL2+H2O+SO2 M(HCL)=36.5 g/mol Vm=22.4 L/mol2*36.5 22.4X=1.46*22.4 / 73X=0.448 Lответ 448 мл
M(AlPo4) = 27 + 31 + 64 = 122 г/моль
M(NaNo3) = 23 + 14 + 48 = 85 г/моль