3Mn⁺⁴O⁻²2+K⁺¹Cl⁺⁵O⁻²3+6K⁺OH⁻=3K⁺¹2Mn⁺⁶O⁻²4+K⁺Cl⁻+3H⁺¹2O⁻²
2Al + 3Br2 → 2AlBr3
54 / 2 × 27 = X / 2
54 / 54 = X / 2
X = 54 × 2 / 54 = 2 моль
а)Н2+Сl2--(t)-->2HCl(хлороводород);