m(р-ра) = 150 г.
W(соли) = 14%= 0,14.
m(соли)= 150×0,14= 21 г.
W(соли) = 100% - 14%= 86%= 0,86.
m(воды)= 150×0,86= 129 г.
Ответ: для приготовления потребуется 21 г соли и 129 г воды.
<span><span>4 <span>Fe</span></span>+<span>6<span>H2O</span></span>+<span>3<span>O2</span></span> → <span>4<span>Fe<span>(OH)</span><span>3</span></span></span></span><span><span>
Fe2<span>(SO4)</span>3</span>+<span>6<span>NaOH</span></span> → <span>2<span>Fe<span>(OH)</span>3</span></span>+<span>3<span>Na2SO<span>4
</span></span></span></span>